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feat(notifier): check if window exists in notification

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This commit is contained in:
Ronan Abhamon 2016-11-16 16:35:52 +01:00
parent 41cab40639
commit d59c34d291
1 changed files with 7 additions and 7 deletions
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14
tests/src/components/notifier/Notifier.cpp
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@ -115,18 +115,18 @@ void Notifier::showNotification (QObject *notification, int timeout) {
Qt::DirectConnection
);
QQuickWindow *window = notification->findChild<QQuickWindow *>();
if (!window)
qFatal("Cannot found a `QQuickWindow` instance in `notification`.");
// Called explicitly (by a click on notification for example)
// or when single shot happen and if notification is visible.
QObject::connect(
notification->findChild<QQuickWindow *>(),
&QQuickWindow::visibleChanged,
[this](const bool &value) {
QObject::connect(window, &QQuickWindow::visibleChanged, [this](const bool &value) {
qDebug() << "Update notifications counter, hidden notification detected.";
if (value) {
if (value)
qFatal("A notification cannot be visible twice!");
return;
}
m_mutex.lock();